Условие:

а) 2(x + 1) = 3(x - 2) и 2(x + 1) + 1 = 3(x - 2) + 1;

б) 2 (x + 1) + x + 2 = 3 (x - 2) + x + 2 и 2 (x + 1) = 3 (x - 2);

в) 2(x + 1) + 1/x = 3(х- 2) + 1/x и 2(x + 1) = 3(x - 2);

г) x = 2 и x + (2-x)/(x+1)=2+(2-x)/(x+1);

д) х + 1 = 2 - х и 2 (x + 1) = 2(2 - x);

е) х+1 = 2- х и х(х + 1) = х(2 - x);

ж) х+1 = 2- х и (х+ 1)(х - 1) = (2 - x)(x - 1);

з) х+1 = 2- х и (х+ 1)(x2 + 2) = (2 - x) (x2 + 2);

и) х+1 = 2- х и (х+ 1)(2х - 1) = (2 - x)(2x - 1)?